A) \[\frac{2}{3}\]
B) \[37\frac{1}{2}\]
C) \[\frac{3}{2}\]
D) \[18\frac{3}{8}\]
Correct Answer: C
Solution :
We have, \[\frac{1+\frac{1}{2}}{1-\frac{1}{2}}\div \frac{4}{7}\left( \frac{2}{5}+\frac{3}{10} \right)\] of \[\left( \frac{\frac{1}{2}+\frac{1}{3}}{\frac{1}{2}-\frac{1}{3}} \right)\] \[=\frac{\frac{3}{2}}{\frac{1}{2}}\div \frac{4}{7}\left( \frac{4+3}{10} \right)\] of \[\left( \frac{\frac{3+2}{6}}{\frac{3-2}{6}} \right)=3\div \frac{4}{7}\left( \frac{7}{10} \right)\] of \[(5)\] \[=3\div \frac{4}{10}\] of \[5=3\div \frac{4}{10}\times 5=3\div \frac{4}{2}=\frac{3}{2}\]
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