A) \[\frac{8}{27}\]
B) \[2\frac{2}{3}\]
C) \[1\frac{1}{3}\]
D) \[\frac{4}{9}\]
Correct Answer: D
Solution :
Let the original fraction be \[\frac{x}{y}.\] According to question, \[\left( \frac{x}{y}+\frac{x}{y} \right)=\frac{16}{81}\] \[\Rightarrow \] \[\frac{{{x}^{2}}}{{{y}^{2}}}=\frac{16}{81}\,\,\Rightarrow \,{{\left( \frac{x}{y} \right)}^{2}}={{\left( \frac{4}{9} \right)}^{2}}\Rightarrow \frac{x}{y}=\frac{4}{9}\]
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