B 
C 
D 
E 
A) A and B
B) B and D
C) E and D
D) A and C
Correct Answer: A
Solution :
Fraction shaded in Figure A =\[\frac{\text{No}\text{. of shaded parts }}{\text{Total no}\text{. of parts}}=\frac{1}{4}\] Fraction shaded in Figure B =\[\frac{\text{No}\text{. of shaded parts }}{\text{Total no}\text{. of parts}}=\frac{2}{8}=\frac{1}{4}\] Fraction shaded in Figure C = \[\frac{\text{No}\text{. of shaded parts }}{\text{Total no}\text{. of parts}}=\frac{2}{4}=\frac{1}{2}\] Fraction shaded in Figure D =\[\frac{\text{No}\text{. of shaded parts }}{\text{Total no}\text{. of parts}}=\frac{3}{4}\] Fraction shaded in Figure E =\[\frac{\text{No}\text{. of shaded parts }}{\text{Total no}\text{. of parts}}=\frac{3}{6}=\frac{1}{2}\] So Figure A and B have one-fourth part shaded.
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