A) [1, 3]
B) \[\left[ \frac{1}{3},\,\,1 \right]\]
C) (1, 3)
D) \[\left( \frac{1}{3},\ 1 \right)\]
Correct Answer: B
Solution :
\[f(x)=\frac{1}{2-\sin 3x},\,\,\sin 3x\in [-1,\,\,1]\] Hence \[f(x)\] lies in \[\left[ \frac{1}{3},\,\,1 \right]\].You need to login to perform this action.
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