A) \[X=Y={{R}^{+}}\]
B) \[X=R,\ Y={{R}^{+}}\]
C) \[X={{R}^{+}},\ Y=R\]
D) \[X=Y=R\]
Correct Answer: C
Solution :
\[f({{x}_{1}})=f({{x}_{2}})\Rightarrow x_{1}^{2}=x_{2}^{2}\Rightarrow {{x}_{1}}={{x}_{2}}\], [if \[X={{R}^{+}}]\] Þ f is one-one. Since \[{{R}_{f}}={{R}^{+}}\subseteq R=Y\]; \ f is not onto.You need to login to perform this action.
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