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JEE Main & Advanced Mathematics Definite Integration Question Bank Fundamental definite integration, Definite integration by substitution

  • question_answer
    \[\int_{0}^{1}{{{\cos }^{-1}}x\,dx=}\]                                      [DSSE 1988]

    A)                 0             

    B)                 1

    C)                 2             

    D)                 None of these

    Correct Answer: B

    Solution :

                    \[\int_{0}^{1}{{{\cos }^{-1}}x\,\,dx=\left[ x{{\cos }^{-1}}x-\sqrt{1-{{x}^{2}}} \right]}_{0}^{1}=1\].


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