A) \[\frac{{{e}^{2}}}{2}+e\]
B) \[e-\frac{{{e}^{2}}}{2}\]
C) \[\frac{{{e}^{2}}}{2}-e\]
D) None of these
Correct Answer: C
Solution :
\[\int_{1}^{2}{{{e}^{x}}\left( \frac{1}{x}-\frac{1}{{{x}^{2}}} \right)\,dx=\left[ \frac{1}{x}{{e}^{x}} \right]_{1}^{2}=\frac{{{e}^{2}}}{2}-e}\].
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