A) \[\log 2/e\]
B) \[\log 4\]
C) \[\log 4/e\]
D) \[\log 2\]
Correct Answer: C
Solution :
\[\int_{1}^{2}{\log xdx=[x\log x-x]_{1}^{2}=2\log 2-2+1}\] \[=\log 4-1=\log 4-\log e=\log \frac{4}{e}\].You need to login to perform this action.
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