JEE Main & Advanced Mathematics Definite Integration Question Bank Fundamental definite integration, Definite integration by substitution

  • question_answer
    \[\int_{\,1}^{\,3}{(x-1)(x-2)(x-3)dx=}\]                                  [Karnataka CET 2002]

    A)                 3             

    B)                 2

    C)                 1             

    D)                 0

    Correct Answer: D

    Solution :

               \[I=\int_{\,1}^{\,3}{(x-1)(x-2)(x-3)dx}\].                 \[I=\int_{\,1}^{\,3}{({{x}^{3}}-6{{x}^{2}}+11x-6)\,dx=\left[ \frac{{{x}^{4}}}{4}-\frac{6{{x}^{3}}}{3}+\frac{11{{x}^{2}}}{2}-6x \right]_{\,1}^{\,3}=0.}\]


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