JEE Main & Advanced Physics Vectors Question Bank Fundamentals of Vectors

  • question_answer The expression \[\left( \frac{1}{\sqrt{2}}\hat{i}+\frac{1}{\sqrt{2}}\hat{j} \right)\] is a

    A)             Unit vector

    B)                                         Null vector

    C)             Vector of magnitude \[\sqrt{2}\]                                                 

    D)             Scalar

    Correct Answer: A

    Solution :

                    \[\vec{P}=\frac{1}{\sqrt{2}}\hat{i}+\frac{1}{\sqrt{2}}\hat{j}\]\\[|\vec{P}|=\sqrt{{{\left( \frac{1}{\sqrt{2}} \right)}^{2}}+{{\left( \frac{1}{\sqrt{2}} \right)}^{2}}}\]= 1             \ It is a unit vector.

adversite


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