A) He has travelled a distance of 700 m
B) His displacement is 700 m
C) His displacement is 500 m
D) His velocity is not uniform throughout the walk
Correct Answer: B
Solution :
Displacement \[\overrightarrow{AC}=\overrightarrow{AB}+\overrightarrow{BC}\] \[AC=\sqrt{{{(AB)}^{2}}+{{(BC)}^{2}}}=\sqrt{{{(400)}^{2}}+{{(300)}^{2}}}=500m\] Distance \[=AB+BC=400+300=700m\]You need to login to perform this action.
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