JEE Main & Advanced Physics Vectors Question Bank Fundamentals of Vectors

  • question_answer The angle made by the vector \[A=\hat{i}+\hat{j}\] with x- axis is             [EAMCET (Engg.) 1999] 

    A)             \[\text{9}0{}^\circ \]          

    B)             \[\text{45}{}^\circ \]

    C)             \[\text{22}.\text{5}{}^\circ \]

    D)             \[\text{3}0{}^\circ \]

    Correct Answer: B

    Solution :

                    \[\vec{A}=\hat{i}+\hat{j}\]Þ \[|A|=\sqrt{{{1}^{2}}+{{1}^{2}}}=\sqrt{2}\]             \[\cos \alpha =\frac{{{A}_{x}}}{|A|}=\frac{1}{\sqrt{2}}=\cos 45{}^\circ \] \ \[\alpha =45{}^\circ \]

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