A) 6
B) \[5\sqrt{2}\]
C) 4
D) \[2\sqrt{10}\]
Correct Answer: D
Solution :
\[\vec{r}={{\vec{r}}_{2}}-{{\vec{r}}_{1}}=(-2\hat{i}-2\hat{j}+0\hat{k})-(4\hat{i}-4\hat{j}+0\hat{k})\] Þ \[\vec{r}=-6\hat{i}+2\hat{j}+0\hat{k}\] \ \[|\vec{r}|=\sqrt{{{(-6)}^{2}}+{{(2)}^{2}}+{{0}^{2}}}=\sqrt{36+4}=\sqrt{40}=2\sqrt{10}\]You need to login to perform this action.
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