A) \[P{{d}^{+2}}\]
B) \[S{{c}^{+2}}\]
C) \[T{{i}^{+4}}\]
D) \[Z{{n}^{+2}}\]
Correct Answer: C
Solution :
\[Ti\,\to \,3{{d}^{2}}4{{s}^{2}}\] \[T{{i}^{+4}}\,\to \,3{{d}^{0}}4{{s}^{0}}\]
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