A) Curium
B) Californium
C) Uranium
D) Terbium
Correct Answer: D
Solution :
Terbium is lanthanide as it belongs to \[4f-\]series having configuration \[[Xe]4{{s}^{9}}6{{s}^{2}}\]. However the remaining members belong to \[5f-\]series (actinides).
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