One mole of this compound has a mass of 42 grams. Its molecular formula is:
A) \[{{C}_{3}}{{H}_{6}}\]
B) \[{{C}_{3}}{{H}_{8}}\]
C) \[C{{H}_{2}}\]
D) \[{{C}_{2}}{{H}_{2}}\]
Correct Answer: A
Solution :
Empirical formula of compound = \[C{{H}_{2}}\] Molecular mass of the compound = 42 \[\therefore n=42/14=3\] \[\therefore \] Hence molecular formula = \[{{C}_{3}}{{H}_{6}}\]
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