A) 5
B) 6
C) 7
D) 8
Correct Answer: C
Solution :
\[\frac{1}{3}(8-r)+r\left( -\frac{1}{5} \right)=0\Rightarrow \frac{8}{3}-\frac{r}{3}-\frac{r}{5}=0\Rightarrow r=5\] Thus term independent of \[x={{\,}^{8}}{{C}_{5}}\times {{\left( \frac{1}{2} \right)}^{3}}{{(1)}^{5}}\] \[=\frac{8\times 7\times 6}{3\times 2\times 1}\times \frac{1}{8}=7\]You need to login to perform this action.
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