A) \[\frac{(2n)!}{n!}{{x}^{2}}\]
B) \[\frac{(2n)!}{n!(n-1)!}{{x}^{n+1}}\]
C) \[\frac{(2n)!}{{{(n!)}^{2}}}{{x}^{n}}\]
D) \[\frac{(2n)!}{(n+1)!(n-1)!}\,{{x}^{n}}\]
Correct Answer: C
Solution :
Middle term = \[{{T}_{\frac{2n+2}{2}}}={{T}_{n+1}}={}^{2n}{{C}_{n}}{{x}^{n}}\]= \[\frac{2n!}{{{(n!)}^{2}}}\,.\,{{x}^{n}}\].You need to login to perform this action.
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