JEE Main & Advanced Mathematics Binomial Theorem and Mathematical Induction Question Bank General term, Coefficient of any power of x, Independent term, Middle term and Greatest term and Greatest coefficient

  • question_answer
    The coefficient of \[{{x}^{5}}\] in the expansion of \[{{(1+x)}^{21}}+{{(1+x)}^{22}}+..........+{{(1+x)}^{30}}\] is [UPSEAT 2001]

    A) \[^{51}{{C}_{5}}\]

    B) \[^{9}{{C}_{5}}\]

    C) \[^{31}{{C}_{6}}{{-}^{21}}{{C}_{6}}\]

    D) \[^{30}{{C}_{5}}{{+}^{20}}{{C}_{5}}\]

    Correct Answer: C

    Solution :

    \[{{(1+x)}^{21}}+{{(1+x)}^{22}}+....+{{(1+x)}^{30}}\] \[={{(1+x)}^{21}}\left[ \frac{{{(1+x)}^{10}}-1}{(1+x)-1} \right]\]= \[\frac{1}{x}[{{(1+x)}^{31}}-{{(1+x)}^{21}}]\] \ Coefficient of x5 in the given expression = Coefficient of x5 in  \[\left\{ \frac{1}{x}[{{(1+x)}^{31}}-{{(1+x)}^{21}}] \right\}\] = Coefficient of x6 in \[[{{(1+x)}^{31}}-{{(1+x)}^{21}}]\] = \[{}^{31}{{C}_{6}}-{}^{21}{{C}_{6}}\].


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