A) \[^{18}{{C}_{9}}\]
B) \[{{-}^{18}}{{C}_{9}}\]
C) \[^{18}{{C}_{0}}\]
D) \[{{-}^{18}}{{C}_{10}}\]
Correct Answer: B
Solution :
If n is even. \[\therefore \]Middle term is 10th term. Þ \[{{T}_{10}}={}^{18}{{C}_{9}}{{(x)}^{9}}.\,{{\left( -\frac{1}{x} \right)}^{9}}=\text{ }-{}^{18}{{C}_{9}}\].
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