JEE Main & Advanced Mathematics Complex Numbers and Quadratic Equations Question Bank Geometry of complex numbers

  • question_answer
    The vector \[z=3-4i\] is turned anticlockwise through an angle of \[{{180}^{o}}\] and stretched 2.5 times. The complex number corresponding to the newly obtained vector is

    A) \[\frac{15}{2}-10i\]

    B) \[\frac{-15}{2}+10i\]

    C) \[\frac{-15}{2}-10i\]

    D) None of these

    Correct Answer: B

    Solution :

    \[3-4i\] i.e., \[(3,-4)\]lie in fourth quadrant in complex plane, after turned anticlockwise through \[{{180}^{o}}\] this will lie in II quadrant, therefore, the number will be \[-3+4i\],  now after stretching it 2.5 times  i.e., multiplying by 2.5, the required complex number will be \[\frac{-15}{2}+10i\].


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