A) 2
B) 3
C) 4
D) 6
Correct Answer: B
Solution :
Let \[z=x+iy\], therefore given equation becomes \[(x+iy)(x-iy)+(2-3i)(x+iy)+(2+3i)(x-iy)+4=0\] Þ\[{{x}^{2}}+{{y}^{2}}+2x+3y-3ix+2iy+2x\] - \[2iy+3ix+3y+4=0\] Þ \[{{x}^{2}}+{{y}^{2}}+4x+6y+4=0\] Therefore given equation represents a circle with radius Radius\[=\sqrt{{{2}^{2}}+{{3}^{2}}-4}=\sqrt{4+9-4}=\sqrt{9}=3\].
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