A) \[y-\]axis
B) A straight line
C) A circle
D) None of these
Correct Answer: C
Solution :
\[|z-3i|=2,\]let \[z=x+iy\] Þ \[|x+i(y-3)|=2\] Squaring both sides, we get \[[{{x}^{2}}+{{(y-3)}^{2}}]=4\] Þ\[{{x}^{2}}+{{y}^{2}}-6y+5=0\]
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