A) \[20{}^\circ \]
B) \[30{}^\circ \]
C) \[40{}^\circ \]
D) \[50{}^\circ \]
Correct Answer: A
Solution :
Given: In \[{{85}^{o}}\] So PQR is an isoceles triangle. And we know, in isoceles A, the angles opposite to the equal sides are equal. \[{{60}^{o}}\] In \[\angle BAC={{45}^{o}}\] Now, \[\angle BED={{120}^{o}}\] (Linear pair) \[\angle ABD\] \[{{15}^{o}}\] \[{{30}^{o}}\] \[{{45}^{o}}\] (\[x={{50}^{o}}\] Sum of all angles in\[\angle CBE={{130}^{o}}\])
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