A) \[\angle A\]
B) \[\angle B\]
C) \[{{60}^{o}}\]
D) \[{{90}^{o}}\]
Correct Answer: C
Solution :
\[{{50}^{o}}\] Since, the transversal BE intersects two parallel lines AB and CD. \[{{60}^{o}}\] \[\angle BAD={{120}^{o}}\] \[\angle BCD\] (\[{{240}^{o}}\] is exterior angle of \[{{60}^{o}}\]) \[{{120}^{o}}\] \[{{180}^{o}}\] \[\angle R={{138}^{o}}\] i.e., \[\angle PQS\]You need to login to perform this action.
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