question_answer

In a Rhombus ABCD, if AB = AC, then \[{{30}^{o}}\]

A)  \[{{40}^{o}}\]                                

B)  \[{{60}^{o}}\]

C)  \[{{90}^{o}}\]                                

D)  \[{{30}^{o}}\]

Correct Answer: B

Solution :

\[ABCD\]  \[\Rightarrow \] \[{{90}^{o}}\] is an equilateral triangle. So \[\square ABCD\], also \[\Rightarrow \]. \[\angle 1=\angle 2=\angle 3=\angle 4={{90}^{o}}\]\[AB=CD\].