question_answer

Two parallel chords on the same side of the centre of a circle are 10 cm and 24 cm long and their distance apart is 7 cm. The radius of the circle is

A) 13cm        

B) 8cm

C) 5cm                            

D) 7cm

Correct Answer: A

Solution :

AP = 12cm and CQ=5cm. AB = 24 cm and CD= 10 cm. Since, the perpendicular to the chord bisects the chord. In  \[\angle BDC={{25}^{o}}\] In  \[\angle BDC\] Subtracting, we have, \[{{85}^{o}}\]                      \[{{120}^{o}}\] \[{{115}^{o}}\] \[{{95}^{o}}\] or  \[\angle PAD={{30}^{o}}\]                              \[\angle CPA={{45}^{o}}\] or  \[\angle CBP\] or  \[{{105}^{o}}\] or  \[{{115}^{o}}\]. \[{{135}^{o}}\] or \[\Delta ABC\], i.e., Radius = 13cm.