question_answer

In figure \[\angle P=\angle R={{100}^{o}}\] If \[\angle S={{75}^{o}}\] The ratio of the areas of \[\angle Q\] and the trapezium BCED is:

A) 3:5                              

B) 9:16

C) 6:9                              

D) None of these

Correct Answer: B

Solution :

First draw \[{{54}^{o}}\] Given: \[{{27}^{o}}\] Let DE = 3x, BC = 5x And  \[{{90}^{o}}\] Now, Area of \[\angle BOD={{120}^{o}}\] Area of \[\angle ACD\] Now, Area of trapezium DEBC = Area of \[{{30}^{o}}\] of\[{{40}^{o}}\] \[{{60}^{o}}\] Ratio of area of \[{{90}^{o}}\] and Area of trapezium                                     \[{{30}^{o}}\]