A) \[AB=BC\]
B) \[AB<BC\]
C) \[AB>BC\]
D) \[AB\le BC\]
Correct Answer: C
Solution :
\[\frac{2}{3}AB=\frac{7}{2}BC=42cm\] \[\frac{2}{3}AB=42\]and\[\frac{7}{2}BC=42\] \[AB=\frac{42\times 3}{2}=63\] \[BC=\frac{42\times 3}{7}=12\] Hence\[AB>BC\] Mind of a mathematician A thoughtful student does not need to do even this calculation. You see that \[\frac{2}{3}rd\] of a quality 'p' is equal to \[\frac{7}{2}th\] of another quantity 'q' Just by mentally thinking about it, quantity \['p'\] will be greater than quantity\['q'\]. Here quantity \['p=AB;\,\,'q'=BC\therefore AB>BC\]
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