A) \[\angle 1=\angle 2\]
B) \[\angle 3=\angle 5\]
C) \[{{180}^{o}}\]
D) \[\angle 1+\angle 3={{180}^{o}}\]
Correct Answer: C
Solution :
\[{{80}^{o}}\] (\[{{100}^{o}}\] Angle in semi-circle is\[90{}^\circ \]) Since, \[\angle DAC={{54}^{o}}\] \[\angle ACB={{63}^{o}}\] \[\angle BAC\] (Half of angle\[{{72}^{o}}\]) Now, \[{{54}^{o}}\] (Linear pair) Consider \[{{27}^{o}}\] \[{{90}^{o}}\] \[\angle BOD={{120}^{o}}\] \[\angle ACD\] \[{{30}^{o}}\]\[{{40}^{o}}\] \[{{60}^{o}}\] \[{{90}^{o}}\] Now, \[{{30}^{o}}\] \[{{45}^{o}}\] \[{{60}^{o}}\] (Sum of angles of\[{{75}^{o}}\]) Now, \[\angle CAD={{50}^{o}}\] (\[\angle BED={{120}^{o}}\] Angles on same arc AD)You need to login to perform this action.
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