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8th Class Mathematics Practical Geometry Question Bank Geometry

  • question_answer
    In the figure given below PS is the diameter. Points P, Q, R, and T, S, R, are collinear. Then, \[{{120}^{o}}\] is equal to

    A)  \[{{360}^{o}}\]                              

    B)  \[{{90}^{o}}\]

    C)  \[{{90}^{o}}\]                                

    D)  \[{{270}^{o}}\]

    Correct Answer: D

    Solution :

    Given:  \[\Delta XYZ\] Now, \[{{60}^{o}}\] (\[{{30}^{o}}\]  Both angles has common arc) \[{{80}^{o}}\] \[{{100}^{o}}\]


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