A) \[{{15}^{o}}\]
B) \[{{30}^{o}}\]
C) \[{{45}^{o}}\]
D) None of these
Correct Answer: B
Solution :
\[x={{30}^{o}}\] is at the center and \[={{360}^{o}}\] is at the remaining part of the circle, so as per theorem, the a \[\times {{180}^{o}}\] \[\angle BAC=\angle ABC+\angle BAC\] \[\therefore \] \[\angle ACD=\angle ABC+\angle BAC\]
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