A) \[70{}^\circ \]
B) \[95{}^\circ \]
C) \[110{}^\circ \]
D) \[120{}^\circ \]
Correct Answer: B
Solution :
In\[\Delta ABC,\,\,\angle A+\angle B+\angle ACB=180{}^\circ \] \[35{}^\circ +110{}^\circ \angle ACB=180{}^\circ \] \[\angle ACB=180{}^\circ -145{}^\circ =35{}^\circ \] In\[\Delta EFD,\,\,\angle E+\angle D+\angle EFD=180{}^\circ \] \[30{}^\circ +100{}^\circ +\angle EFD=180{}^\circ \] \[\angle EFD=180{}^\circ -130{}^\circ =50{}^\circ \] In \[\Delta FCG,\]\[\angle FGC+\angle GCF+\angle CFG=180{}^\circ \] \[\angle FGC+35{}^\circ +50{}^\circ =180{}^\circ \] \[\angle FGC=180{}^\circ -85{}^\circ =95{}^\circ \] \[\angle FGC=\angle x=95{}^\circ \] (Opposite angles)
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