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5th Class Mathematics Geometry Question Bank Geometry

  • question_answer
    An equilateral triangle ABC is inscribed in a circle of centre as follows: \[\angle BOC\] will be equal to:

    A)  \[{{60}^{o}}\]                                

    B)  \[{{90}^{o}}\]             

    C)  \[{{120}^{o}}\]                  

    D) None of above

    Correct Answer: C

    Solution :

     \[\Delta ABC\]is equilateral \[\Delta \]. \[\therefore \] \[\angle A=\angle B=\angle C={{60}^{o}}\] So, \[\angle BOC=2\angle A=2\times {{60}^{o}}={{120}^{o}}\]  


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