Given\[\angle x:\angle y=3:2\], find\[\angle x\].
A) \[{{70}^{o}}\]
B) \[{{42}^{o}}\]
C) \[{{140}^{o}}\]
D) \[{{81}^{o}}\]
Correct Answer: B
Solution :
\[\angle COB=\angle AOD={{70}^{o}}=\angle x+\angle y\] \[\angle x:\angle y=3:2\] \[\therefore \]units\[={{70}^{o}}\] Thus, \[1\]unit\[=\frac{{{70}^{o}}}{5}={{14}^{o}}\] \[\angle x=3\]units\[=3\times {{14}^{o}}={{42}^{o}}\]
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