Given that\[\angle AOB=\angle DOC\], find\[\angle p\].
A) \[{{44}^{o}}\]
B) \[{{46}^{o}}\]
C) \[{{51}^{o}}\]
D) \[{{92}^{o}}\]
Correct Answer: B
Solution :
\[\angle AOB=\angle DOC\] \[\Rightarrow \]\[\angle AOB=\frac{{{180}^{o}}-{{88}^{o}}}{2}={{46}^{o}}\] \[\angle p=\angle AOB={{46}^{o}}\]
You need to login to perform this action.
You will be redirected in
3 sec
