Find the respective values of\[\angle w,\,\,\angle x,\,\,\angle y\]and\[\angle z\].
A)
\[\angle w\] \[\angle x\] \[\angle y\] \[\angle z\] \[{{24}^{o}}\] \[{{72}^{o}}\] \[{{120}^{o}}\] \[{{144}^{o}}\]
B)
\[\angle w\] \[\angle x\] \[\angle y\] \[\angle z\] \[{{24}^{o}}\] \[{{72}^{o}}\] \[{{144}^{o}}\] \[{{120}^{o}}\]
C)
\[\angle w\] \[\angle x\] \[\angle y\] \[\angle z\] \[{{24}^{o}}\] \[{{120}^{o}}\] \[{{72}^{o}}\] \[{{144}^{o}}\]
D)
\[\angle w\] \[\angle x\] \[\angle y\] \[\angle z\] \[{{24}^{o}}\] \[{{120}^{o}}\] \[{{144}^{o}}\] \[{{120}^{o}}\]
Correct Answer: A
Solution :
Given,\[\angle w:\angle x:\angle y:\angle z=1:3:5:6\] \[1+3+5+6=15\]units \[15\]units\[=360{}^\circ \] \[1\]unit \[=360{}^\circ \div 15=24{}^\circ \] \[3\]units\[=3\times {{24}^{o}}={{72}^{o}}\] \[5\]units\[=5\times {{24}^{o}}={{120}^{o}}\] \[6\]units\[=6\times {{24}^{o}}={{144}^{o}}\]
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