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8th Class Mathematics Practical Geometry Question Bank Geometry

  • question_answer
    C is the centre of the circle as shown in the below diagram. Then, \[{{40}^{o}}\] is equal to

    A)  \[{{50}^{o}}\]                                

    B)  \[{{60}^{o}}\]

    C)  \[\angle BAD={{120}^{o}}\]                     

    D)  \[\angle BCD\]

    Correct Answer: A

    Solution :

    Vertically opposite angles are equal. Hence, \[AB||DC\] Also  \[AB||DC,AD||BC\] \[AB=CD,AD=BC\] \[OA=OC,OB=OD\]or \[AC\ne BD\]or\[ABCD\]


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