A) \[y=0.05\sin 2\pi (4000\,t-12.5\,x)\]
B) \[y=0.05\sin 2\pi (4000\,t-122.5\,x)\]
C) \[y=0.05\sin 2\pi (3300\,t-10\,x)\]
D) \[y=0.05\sin 2\pi (3300\,x-10\,t)\]
Correct Answer: C
Solution :
Here \[A=0.05m,\] \[\frac{5\lambda }{2}=0.025\]Þ \[\lambda =0.1m\] Now standard equation of wave \[y=A\sin \frac{2\pi }{\lambda }(vt-x)\]Þ \[y=0.05\sin 2\pi (33t-10x)\]
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