A) \[{{y}_{\max }}=20m\]
B) \[{{y}_{\max }}=15m\]
C) \[{{y}_{\max }}=11m\]
D) \[{{y}_{\max }}=5m\]
Correct Answer: C
Solution :
Work done = Gain in potential energy Area under curve = mgh Þ \[\frac{1}{2}\times 11\times 100=5\times 10\times h\] Þ \[h=11m\]You need to login to perform this action.
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