A) \[9.25\,m{{s}^{-1}}\]
B) \[5\,m{{s}^{-1}}\]
C) \[14.25m{{s}^{1}}\]
D) \[4.25m{{s}^{1}}\]
Correct Answer: C
Solution :
Impulse = Change in momentum \[=m({{v}_{2}}-{{v}_{1}})\] ?(i) Again impulse = Area between the graph and time axis \[=\frac{1}{2}\times 2\times 4+2\times 4+\frac{1}{2}(4+2.5)\times 0.5+2\times 2.5\] \[=4+8+1.625+5\] \[=18.625\] ...(ii) From (i) and (ii), \[m({{v}_{2}}-{{v}_{1}})=18.625\] Þ\[{{v}_{2}}=\frac{18.625}{m}+{{v}_{1}}=\frac{18.625}{2}+5=14.25\ m/s\]
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