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JEE Main & Advanced Physics Simple Harmonic Motion Question Bank Graphical Questions

  • question_answer
    For a particle executing S.H.M. the displacement x is given by \[x=A\cos \omega t\]. Identify the graph which represents the variation of potential energy (P.E.) as a function of time t and displacement x                      [IIT JEE (Screening) 2003]

    A)            I, III                                          

    B)            II, IV

    C)            II, III                                         

    D)            I, IV

    Correct Answer: A

    Solution :

                       Potential energy is minimum (in this case zero) at mean position (x = 0) and maximum at extreme position \[(x=\pm A).\] At time t = 0, x = A, hence potential should be maximum. Therefore graph I is correct. Further in graph III. Potential energy is minimum at x = 0, hence this is also correct.


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