JEE Main & Advanced Physics NLM, Friction, Circular Motion Question Bank Graphical Questions

  • question_answer
    A particle of mass m moving with velocity u makes an elastic one dimensional collision with a stationary particle of mass m. They are in contact for a very short time T. Their force of interaction increases from zero to F0 linearly in time T/2, and decreases linearly to zero in further time T/2. The magnitude of F0 is

    A)                                 \[mu/T\]                

    B)                                 \[2mu/T\]                

    C)                                 \[mu/2T\]                

    D)                                    None of these

    Correct Answer: B

    Solution :

                                    In elastic one dimensional collision particle rebounds with same speed in opposite direction                 i.e. change in momentum \[=2mu\] But Impulse \[=F\times T=\]Change in momentum                 Þ \[{{F}_{0}}\times T=2mu\]Þ \[{{F}_{0}}=\frac{2mu}{T}\]                 


You need to login to perform this action.
You will be redirected in 3 sec spinner