Answer:
The value of \['g'\] on the surface of moon is about \[\frac{1}{6}th\] of its value on the surface of earth. For the same gain of P.E. in both cases, we have \[m{{g}_{m}}{{h}_{m}}=m{{g}_{e}}{{h}_{e}}\] or \[{{h}_{m}}=\frac{{{g}_{e}}{{h}_{e}}}{{{g}_{m}}}=\frac{{{g}_{e}}{{h}_{e}}}{{{g}_{e}}/6}=6{{h}_{e}}\]
You need to login to perform this action.
You will be redirected in
3 sec