Answer:
In the first case,\[{{V}^{2}}={{0}^{2}}=2gh\Rightarrow {{V}^{2}}=2gh\,\,or\,\,2g=\frac{{{V}^{2}}}{h}\] In the second case, \[{{(2V)}^{2}}-{{V}^{2}}=2gs\] \[\Rightarrow 3{{V}^{2}}=\frac{{{V}^{2}}}{h}\times s\Rightarrow s=3h\]
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