A) \[\frac{{{10}^{2}}}{50}\]
B) \[\frac{{{10}^{2}}}{0.50}\]
C) \[\frac{{{10}^{5}}}{50}\]
D) \[\frac{{{10}^{5}}}{0.0050}\]
Correct Answer: C
Solution :
Area =\[\pi {{\text{r}}^{\text{2}}}\text{=0}\text{.50m}{{\text{m}}^{\text{2}}}\text{=0}\text{.0050 c}{{\text{m}}^{\text{2}}}\] Let L be its length. So volume, \[\text{V = 0}\text{.0050L c}{{\text{m}}^{\text{3}}}\] Weight in air, \[{{\text{W}}_{a}}=75g\] Weight in water, \[{{W}_{W}}=65g\] So buoyant force of water\[={{W}_{a}}-{{W}_{W}}=10g\] \[\text{= V }\times \]density of water \[\times g\] or \[10=0.0050L\times 1\] \[L=\frac{10}{0.0050}=\frac{10\times {{10}^{4}}}{50}=\frac{{{10}^{5}}}{50}cm\]
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