A) Cl
B) \[C{{l}^{+}}\]
C) \[C{{l}^{-}}\]
D) All
Correct Answer: A
Solution :
\[Cl-Cl\xrightarrow{\text{U}\text{.V}}\underset{\text{Free}\,\,\text{radical}}{\mathop{Cl+Cl}}\,\]
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