A) \[O{{F}_{2}}\]
B) \[{{O}_{3}}\]
C) \[{{O}_{2}}\]
D) \[HF\] and \[{{O}_{2}}\]
Correct Answer: A
Solution :
\[O{{F}_{2}}+(dil.)\,2NaOH\to 2NaF+{{O}_{2}}+{{H}_{2}}O\]
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