A) Alcohol
B) Chloroform
C) Sodium hydroxide
D) Potassium iodide
Correct Answer: D
Solution :
Iodine has the least affinity for water and is only slightly soluble in it. However, it dissolves in 10% aq. solution of KI due to the formation of a complex ion i.e. \[2NaCl+2{{H}_{2}}O\,\,\to \,\,2NaOH+\underset{\text{(anode)}}{\mathop{C{{l}_{2}}}}\,+\underset{\text{(cathode)}}{\mathop{{{H}_{2}}}}\,\]. \[{{I}_{2}}+KI\] ⇌\[2{{F}_{2}}+2{{H}_{2}}O\,\to \,4HF+{{O}_{2}}\] or \[{{I}_{2}}+{{I}^{-}}\] ⇌ \[I_{3}^{-}\] (complex ion)
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