A) Electrolysis of \[NaCl\]
B) Electrolysis of brine
C) Electrolysis of bleaching powder
D) All of these
Correct Answer: B
Solution :
\[2NaCl+2{{H}_{2}}O\,\xrightarrow{\text{Electrolysis}}\]\[\underset{\text{(aq)}}{\mathop{2NaOH}}\,+\underset{\text{(}g\text{)}}{\mathop{C{{l}_{2}}}}\,+\underset{(g)}{\mathop{{{H}_{2}}}}\,\]
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